homecyberdefense
Calculators
General
Algebra
Geometry
Coordinate-geometry
Statistics
Calculus
Qna
Math
homecyberdefense
homecyberdefense
Home
General
Algebra
Geometry
Coordinate-geometry
Statistics
Calculus
Qna
Math
MATH SOLVE
Home
General
Help plz and explain
4 months ago
Q:
Help plz and explain
Accepted Solution
A:
Given x, y, a, b are positive numbers
[tex]x^{-2/3}=a^{-2}=>x^{-1/3}=\pm{a^{-1}}=>x^{-1/3}=a^{-1}........[x,a >0][/tex]
[tex]y^{2/3}=b^4=>y^{1/3}=\pm{b^2}=>y^{1/3}=b^2..........[y,b >0][/tex]
[tex](xy)^{-1/3}=x^{-1/3}*y^{-1/3}[/tex]
[tex]=x^{-1/3}*y^{-1/3}[/tex]
[tex]=a^{-1}*b^{-2}[/tex]
[tex]=\frac{1}{ab^2}[/tex].